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=-0.002Y^2+0.006Y
We move all terms to the left:
-(-0.002Y^2+0.006Y)=0
We get rid of parentheses
0.002Y^2-0.006Y=0
a = 0.002; b = -0.006; c = 0;
Δ = b2-4ac
Δ = -0.0062-4·0.002·0
Δ = 3.6E-5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.006)-\sqrt{3.6E-5}}{2*0.002}=\frac{0.006-\sqrt{3.6E-5}}{0.004} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.006)+\sqrt{3.6E-5}}{2*0.002}=\frac{0.006+\sqrt{3.6E-5}}{0.004} $
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